Home Forums Archive Structure Designs \$10,000 Seastead

This topic contains 31 replies, has 6 voices, and was last updated by  shredder7753 4 years, 9 months ago.

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• #1450

tusavision
Participant

shredder7753 wrote:

tusavision wrote:

shredder7753 wrote:

man i really didnt want to engage u anymore but… ur so full of it. you cant even do one thing for \$10K. i will worship the water you ‘stead on if you can explain how to get ur lil doggies to stay put in the same place for 2 months. DP and mooring cant be done for 10k.

So is what you’re saying is: you concede that you can’t do it for \$100,000 dollars and you accept my challenge?

[/quote]

absolutely. bring it.

[/quote]

1)Structure

Concrete Platform

200^2 ft =3.14r^2 -> circle with <9' radius.

<9' radius circle 1' deep= 200 cubic ft of concrete

unit conversion: 1yard^3=27ft^3

200/27-> 7.4 cubic yards of concrete.

Concrete Pricing: (reference source #1)

Price of concrete: \$75/cubic yard

Price of Subbase: \$12/cubic yard

Price of Forms: \$1.50/sq. ft = \$300

Price of Reinforcement: \$.1/sq. ft = \$20

7.4*75=\$555

Conclusion:

Price of materials ->\$663

Price of Labor -> \$300

Total: \$963

ETFE Bubble Dome:

Surface area of a 9′ radius sphere=4*3.14*9^2= 1020sq./ft

Surface area of a 9′ radius hemisphere = 1/2*1020=510sq./ft

Theoretical ETFE sheet pricing: \$.05sq./ft (reference source #2)

510*.05=\$26 (no scrap price)

Conclusion:

510sq/ft ETFE plastic sheet=\$26

Conservative Figure ETFE Bubble Dome:

ETFE Sheet Pricing(reference source #3)

12’x12’=\$471.65

12×12=144sq./ft

510/144=4

4*471.65=\$1900

Conclusion:

510sq/ft ETFE plastic sheet=\$1900

2) Equipment

Life Support

Scuba Compressor: \$3,154.95 (reference source #4)note: I wouldn’t actually spend this much but for argument sake I’ll pretend I’m this bad at cutting costs.

Volume of seastead = 4/3*3.14*9^3 = 3060 cubic feet

Human consumption of air=60 liters/minute (reference source #5)

Unit Conversion1 liter= .0354ft cubic feet

60*.0354 = 2.12 cubic feet / minute

3060/2=1530 cubic feet per dog

1530/2.12=720 minutes of breathable air per dog

720/60=12 hours breathable air per dog.

The longest lasting hurricane on record lasted 28 days.(reference source #6)

That translates to 56 times our seastead’s capacity. Any sane person would at this point do something simple like:

-move their seastead to a location less hurricane prone

-rate the seastead as a storm shelter to a limited time span.

[text editor is bugging out continuing in next post]

reference sources

#12545

tusavision
Participant

continued from last post:

That would make sense, but I’m so awesome I don’t have to play by the rules of sane people.

Every 10 meters of depth in water adds 1 atmosphere to ambient pressure. By using high pressure hose and a SCUBA regulator, I can store air at a pressure of 3000 PSI above ambient. pnuematic hose and a SCUBA regulator, I can store air at 200 PSI above ambient pressure.

We need to fit 56 units of gas in X units volume. Given a value of 56*3060(2 dogs worth) we have to store 171360 cubic feet of gas.

If we had higher pressure equipment, we could store this gas at any depth, but because we are artificially limiting ourselves to off the shelf SCUBA/welding gear: 3000 psi pressure differential it is. 200 psi pressure differential it is.

200psi =14 ATM or 140 meters worth of pressure differential

(Original volume / # of ATM) gives us change in volume.

171360/14= 12240 cubic feet

So, at 140 meters pressure differential we need a 12240 cubic foot capacity bagpipe in order to store 28 days worth of air.

As we remember from our earlier post, volume of a sphere is equal to “4/3*3.14*x^3 = 700 cubic feet ” or X^3=167.2

Hefty trash bag= 30 gallons

1 gallon = .134 cubic feet

30*.134= 4. cubic feet.

700/4=176* 30 gallon bags

Hefty 30 gallon bags=\$12/40 count(reference #7)

176/40=4.4

4.4*12=\$53

Conclusion:

28 days worth of trashbags: \$60

Continued in next post…

Reference sources

#12546

tusavision
Participant

330 ft=10atm

171360/10=17136 cubic ft of air

17136/4=4284 trash bags

4284/40=108 boxes of trash bags

\$1285.2 spent on 4290 trash bags full of air.

330ft of 200 psi airhose

350/50ft=7 airhoses

\$20/50 ft of air hose

\$140 on air hose.

Total money spent on 28 day air storage/snorkel system \$1330

#12547

tusavision
Participant

tusavision wrote:

330 ft=10atm

171360/10=17136 cubic ft of air

17136/4=4284 trash bags

4284/40=108 boxes of trash bags

\$1285.2 spent on 4290 trash bags full of air.

330ft of 200 psi airhose

350/50ft=7 airhoses

\$20/50 ft of air hose

\$140 on air hose.

Total money spent on 28 day air storage/snorkel system \$1330

I’ll finish it tomorrow. I still have to design the solar/wind/water/wave water systems, and design a diesel fuel tank. Once I have a bill of materials I’ll write the Operational Procedures the ship will follow to keep the dogs alive for 2 months.

#12549

shredder7753
Participant

interesting, so far. holding further comments.

#12551

elspru
Participant

tusavision wrote:

tusavision wrote:

330 ft=10atm

171360/10=17136 cubic ft of air

17136/4=4284 trash bags

4284/40=108 boxes of trash bags

\$1285.2 spent on 4290 trash bags full of air.

330ft of 200 psi airhose

350/50ft=7 airhoses

\$20/50 ft of air hose

\$140 on air hose.

Total money spent on 28 day air storage/snorkel system \$1330

I’ll finish it tomorrow. I still have to design the solar/wind/water/wave water systems, and design a diesel fuel tank. Once I have a bill of materials I’ll write the Operational Procedures the ship will follow to keep the dogs alive for 2 months.

[/quote]

Hey, you can save yourself a lot of headache by simply using a biological air-support system.

Nature has been here to provide air for billions upon billions of years.

Probably cost you under \$500 in total, for infinity high quality air.

calm aware desire choice love express intuit move

#12557

OCEANOPOLIS
Participant

Is this a \$10,000.00 substead for dogs?

#12559

TheTimPotter
Participant

Trash bags?

#12571

shredder7753
Participant

#12572

OCEANOPOLIS
Participant

the trash bags are for the dog poop ?

#12567

tusavision
Participant

Price of Ammonium Nitrate \$934.12/ton (reference source #8)

NH4NO3(s) —–>N2O(g) +2H2O(L) (reference source #9)

Moles N2O = 35 g / 44 g/mol= 0.795
the ratio is 1 : 1
Moles NH4NO3 needed = 0.795
Mass NH4NO3 = 0.795 mol x 80 g/mol= 63.6 g of NH4NO3 required to produce 35g of N2O

Catalytic Decomposition of Nitrous Oxide

activation energy: 1000°C(thermal) >200°C(catalytic)

reaction enthalpy: 82kJ/Mol

reaction temperature: 1300 °C (reference source #10)

2N2O(g) —> 2N2(g) + O2(g) + Heat (reference source #11)

97.7°F = Critical Temperature of N2O (reference source #12)

1069-1278 psi = Critical Pressure of N2O

Density(liquid @ 86°F) = 39.1 lb/cubic feet

Water Capacity of a AL80 SCUBA tank: 678 Cubic Inches(0.392361 ft³)

15.34lbs N20(86°F liquid) per SCUBA tank

44.013 g/mol n2o

1.977 g/L (gas)

Reference Sources

#12573

tusavision
Participant

shredder7753 wrote:

What question?

No, the trash bags are for storing liquid water and air compressed to 33 ATM (1/33 it’s volume at 1 ATM)

#12574

shredder7753
Participant

tusavision wrote:

shredder7753 wrote:

What question?

No, the trash bags are for storing liquid water and air compressed to 33 ATM (1/33 it’s volume at 1 ATM)

[/quote]

u specified 200 NM offshore.

stationkeeping!

#12575

tusavision
Participant

tusavision wrote:

Price of Ammonium Nitrate \$934.12/ton (reference source #8)

NH4NO3(s) —–>N2O(g) +2H2O(L) (reference source #9)

Moles N2O = 35 g / 44 g/mol= 0.795
the ratio is 1 : 1
Moles NH4NO3 needed = 0.795
Mass NH4NO3 = 0.795 mol x 80 g/mol= 63.6 g of NH4NO3 required to produce 35g of N2O

Catalytic Decomposition of Nitrous Oxide

activation energy: 1000°C(thermal) >200°C(catalytic)

reaction enthalpy: 82kJ/Mol

reaction temperature: 1300 °C (reference source #10)

2N2O(g) —> 2N2(g) + O2(g) + Heat (reference source #11)

97.7°F = Critical Temperature of N2O (reference source #12)

1069-1278 psi = Critical Pressure of N2O

Density(liquid @ 86°F) = 39.1 lb/cubic feet

Water Capacity of a AL80 SCUBA tank: 678 Cubic Inches(0.392361 ft³)

15.34lbs N20(86°F liquid) per SCUBA tank

44.013 g/mol n2o

1.977 g/L (gas)

Reference Sources

1 pound = 453.59237 grams

15.34*453.59=6958.7 grams of N2O per scuba tank (3519.8 Liters at 1 ATM)

Therefore:

1 AL80 SCUBA tank holds 158 mol of n2o

remembering that:

2N2O(g) —> 2N2(g) + O2(g) + Heat (reference source #11)

158N2O= 158N2 + 79O2

158(28.0134 g)+79(31.9989 g)=AL80 tank air production capacity in grams

4426+2527.9 = 6953.9 grams of air

weight of air = 1.294 kg/m3

5.37m^3 of air per scuba tank

1 cubic meter = 35.3146667 cubic feet

189.639 = cubic feet of air per AL80 scuba tank

energy produced per AL80 of N2O converted to air:

82kJ/Mol

158*82=12956kJ

Now that we know we want 158 mol of n2o, we can calculate the weight, volume, and price of the NH4NO3 precursor.

NH4NO3(s) —–>N2O(g) +2H2O(L)

158(NH4NO3)= 12646.85 grams of NH4NO3

12.647 kg of NH4NO3 = 1 AL80 of N2O + 316(18.0153 g water)

water production of 12.647 kg of NH4NO3 = 5.69kg h2o

#12576

tusavision
Participant

shredder7753 wrote:

tusavision wrote:

shredder7753 wrote:

What question?

No, the trash bags are for storing liquid water and air compressed to 33 ATM (1/33 it’s volume at 1 ATM)

[/quote]

u specified 200 NM offshore.

stationkeeping!

[/quote]

So long as I don’t get within 200 nm of land, I don’t have to stationkeep.

Particually if I’m in a gyre.

Otherwise, by controlling the buoyancy of the platform I can move in and out of wind/currents depending on their direction.

I also have more monopropellant than it would take to launch a satellite.

So stationkeeping isn’t a question. It’s trivial.

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